// Version: 1.0 - Employee モデル定義（簡易 POJO）
class Employee {
  final int? id;
  final String name;
  final String email;
  final String tel;
  final String department;
  final String role;
  final DateTime createdAt;
  
  Employee({
    this.id,
    required this.name,
    required this.email,
    required this.tel,
    required this.department,
    required this.role,
    this.createdAt = DateTime.now(),
  });

  // JSON シリアライゼーション（簡素版）
  Map<String, dynamic> toJson() => {
        'id': id,
        'name': name,
        'email': email,
        'tel': tel,
        'department': department,
        'role': role,
        'created_at': createdAt.toIso8601String(),
      };

  // JSON デシリアライゼーション（簡素版）
  factory Employee.fromJson(Map<String, dynamic> json) => Employee(
        id: json['id'] as int?,
        name: json['name'] as String,
        email: json['email'] as String,
        tel: json['tel'] as String,
        department: json['department'] as String,
        role: json['role'] as String,
      );

  // 深コピー用メソッド（編集時の使用）
  Employee copyWith({
    int? id,
    String? name,
    String? email,
    String? tel,
    String? department,
    String? role,
    DateTime? createdAt,
  }) => Employee(
        id: id ?? this.id,
        name: name ?? this.name,
        email: email ?? this.email,
        tel: tel ?? this.tel,
        department: department ?? this.department,
        role: role ?? this.role,
        createdAt: createdAt ?? this.createdAt,
      );

  @override
  String toString() => 'Employee(id: $id, name: $name)';
}